The groups of the 2014 ATP World Tour Finals (Original photos: Getty Images; Montage: BATennis World)
The groups of the 2014 ATP World Tour Finals
(Original photos: Getty Images; Montage: BATennis World)

The draw for the ATP World Tour Finals has been made on Monday and the groups can only be described as such: the Grand Slam winners and the Group of Death.

Group A: The Grand Slam winners

It is only the coincidence of the draw that placed all of this year’s Grand Slam champions taking part in the event in the same group. Led by the two-time defending champion, Novak Djokovic (Wimbledon), the group also includes Stan Wawrinka (Australian Open), Tomas Berdych, and Marin Cilic (U.S. Open).

It is difficult not to predict that the world number one will top the group, as Djokovic has a combined 41-5 head-to-head against his rivals, on top of being in a 27-match winning streak on indoor courts.

Group B: The Group of Death

The second group is comprised of Roger Federer, Kei Nishikori, Andy Murray, and Milos Raonic and it is safe to say that for all involved, it really is the “group of death”.

Group B is so well balanced that even Federer does not have any advantage whatsoever, save his experience in a tournament he has won six times in the past. After all, Federer does have a 19-14 combined head-to-head against his group rivals, which includes two players (Nishikori and Raonic) who are taking part in the year-end event for the first time. As for Andy Murray, it will be a solid test in order to see if his recent form is there to stay.